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- forward(length * 2) # we multiply by two so the distance tracy travels is doubled. for i in range(5): square() length = length + 10 #length increase by 10 each square. simple math. if the length is 10, the distance traveled is 20. if the length is 20, the distanced traveled is 40. if the length is 30, the distanced traveled is 60. |
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Aug 10, 2009 · forward (length * 2) # we multiply by two so the distance tracy travels is doubled. length = length + 10 #length increase by 10 each square. simple math. if the length is 10, the distance traveled is 20. if the length is 20, the distanced traveled is 40. if the length is 30, the distanced traveled is 60. > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >
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Sep 14, 2016 · undo() The undo() function will undo the turtle's last action. It will be as though the last action was never made. For example, if the last action was a call to the forward(100) function, calling undo will move the turtle backwards 100 steps and erase any line that was drawn. (This is from CODEHS) I've already tried out the code in my head and I keep getting stuck at 9. Apparently the answer is 10? This doesn't make any sense because on the 9th iteration of the while loop, you add 2 to 9 (stairsWalked), 9 + 2 = 11, you can't go through the if statement anymore and are stuck at 11 and thus, exit the while loop.
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